Connect the Red/White wire through a fuse to the #30 post on the relay. This is the "source" power. Connect the bike's Black (Ignition) wire from the harness (cut it away from the keyswitch) to the #87 terminal on the relay (this is "switched power", then). Connect the Black that you cut from the key to the #85 terminal, and connect the #86 terminal to Green (ground). These last 2 are the coil of the relay: when you now turn on the Key, it connects the Red/White (through the fuse) to the Black. The Brn/Brn-Wht wires stay on the keyswitch, and control the Park light and taillight stuff.
"Holy crap!", said the blind man. I think I got it.
So let me just run through this.
Red wire from battery goes up to the 15a fuse then to the key switch. When switched, power goes through the black wire on the key switch down to my relay to the 85 terminal then from the 86 terminal to ground.
Red/white wire is first fused with a 15a fuse then connected to terminal 30 and then the other side of the black wire is connected to terminal 87 and then I'm good as gold.
But is the magnet side of the relay a resistor? Or will the way I explained it blow the 15a fuse on the solid red wire?
Man, you guys are patient. I'm trying as hard as I can to learn.
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1978 Honda CB550K