Lets use ohm's law, OK?
With the points closed, and a battery at 12V. you have known 1 ohm and 3 ohm resistance in series with the supplied power.
1+3 = 4 ohms total.
12v /4 ohms = 3 amps current draw. (E / R = I)
3 amps drawn through a 1 ohm resistor consumes 3 volts. ( R X I = V)
12 V - 3 v (dropped by the resistor) is 9 V, that you can expect to get to the coil in a perfect world.
I'd guess you have some more resistance in the path to the coils that would account for the other volt lost at the coil. Could be contact resistance on the switches or connectors between coil and battery terminal. You can find these devices with a wire diagram of your bike. But, I don't think the 1 volt loss unaccounted for, is the cause of your bike not running.
Cheers,