Makes you wonder if this is one of the reasons why light cannot escape a powerful gravitational field (a.k.a. black hole), besides the fact that light carries momentum and therefore has mass.
Gravity is pretty gnarly
Yes, gravity is pretty gnarly, and light has momentum, but it actually
doesn't have mass. How do we know light is massless... for one thing, it travels
at the speed of light. No massive particle can do that (assuming physics as we know it is not wrong). (By the way, because light has
momentum is why it can produce a pressure on an object, even though it has no mass. Just a curious thing I figured I'd throw in.)
So one may ask then how does gravity "bend" light, or keep it from escaping a black hole?
Einstein postulated in his general theory of relativity that massive objects warp this thing called 'space-time'. The photon of light follows the 'easiest' path (nature is lazy), called a geodesic, which happens to follow the warped space-time, and alters the trajectory of the light.
So how is it that light can't escape a black hole?
First a definition (MarkCB750 is probably peeing his pants with joy about not having to think about defining it himself)
A
black hole is
anything from which light cannot escape. (Are you happy MarkCB749?)
If light can't escape, and nothing can travel faster than light, then
nothing can escape (barring Hawking radiation...).
In order for something to escape the gravitational pull of a massive object (that is, to not be gravitationally
bound to the massive object), it has to reach
escape velocity. The astronauts that went to the moon had to reach or exceed Earth's escape velocity (something like 11 km/s).
We can calculate the escape velocity if we equate the kinetic energy to the potential energy:
mv
2/2 = GmM/r,
where m = the mass of the object trying to 'escape',
M = mass of the other object (earth, black hole, moon, etc.),
r = distance between the masses,
v = velocity.
If we do the algebra, 'm' cancels from both sides, and we get for the escape velocity:
v
escape = √(2GM/r)
where √ is the square root. If you plug in the mass and radius of the earth, in consistent units, you can get the 11 km/s escape velocity.
If we ask what happens if v = c (the speed of light), and keep in mind that c is the fastest anything can go, we can solve the above equation for the distance ('r') and get
r = 2GM/c
2.
Anything within this distance cannot escape the gravitational pull of the object with mass M. This value of 'r' is called the "Schwarzschild radius". In terms of the black hole, it is the "event horizon".
Notice that M was never specified (to the fuming malcontent of MarkCB748). You can plug in
your mass and calculate
your Schwarzschild radius! Every massive object has one (even MarkCB747). And if you were to somehow be compressed into a volume with a radius smaller than your Schwarzschild radius,
you would become a black hole!
The more carefully calculated Schwarzschild radius calculation, taking general relativity into account (we didn't in the above calculation!) oddly gives the same answer as our naive calculation. That is, our naive calculation gives the answer that is consistent with general relativity. It's one of those little things that happens from time to time.