Eh, I'm freaking myself out, math is hard without coffee. PJ, can you give us the formula you used for "you need about 107cc @ 11,500 rpm for a 14:1 F/A ratio on a CB350"
I'll have to look it up, I was tired, should have said its for a 13:1 F.A. ratio not a 14:1 F/A
Anyway, this is as much of formula as I can remember at present
You know cylinder size,
350/2 =175cc
you know max rpm =11,500
its a four stroke so you half that 11,500/2= 5750 ( 'sucks' every other stroke)
5750 x 175 = 1006250cc/min which is about 1.0cu/M, use 1.1 for safety, slightly rich is better than slightly lean
air density is approx 1.275Kg/cu.Meter at sea level,
1.1 x 1.275 = 1.4Kg air/min = 1400gm/min
fuel is about 1000Kg/cu.M, or, about1 gram/cc.
1,400 divided by 12.5 (fuel air ratio we want) = 112gm/min
1gm = 1cc fuel
therefore it equals a 112 main jet, if flow is in cc/min
The original number (107) was for CB350 (326cc)
This gives you a starting point which can vary by +/- 20%, depending on exhaust, air filters, cam, etc
I'm sure I missed something, that seems too easy
?
It does seem to give a usable jet size though???
PJ OK, I looked it up
Its from Streetfighters magazine article a few years ago,
Phat Bob's Calc's, Part 1- Fuel
The formula is this:-
Q (in cc/min)=C x A x [(2 x RHO x (P1-P2)]^1/2/RHO Volume of flow of incompressible liquid (fuel)
through jet of area A = Q
discharge coefficient, = C (variable, probably 0.6~0.65)
pressure drop across jet = P1-P2
density of fuel (approx 1000kg/cu Meter) = RHO
Main jet size =A
I think I only use part of this formula ?