Here's what I understand. The black is used by someone that wants to use the rear turn signals as running lights, turn signals, and brake lights. In this case, the original poster is using that box WITH a tail/brake light, so he has to compensate for conditions that the manufacturer of the box didn't intend.
Correct.... The control module was designed for a single filament system... but because I have a dual filament system, I have to join the running light wire and the brake light wire to create a single filament system.... The resistor in the running light system (brown wire) is only there to knock the voltage down so that it causes a distinct difference between the running light and brake light like a single filament system would function....
THE CONTROL MODULE:
The only thing that the control module does is turn your turn signals into running and brake lights.... in order to do that, the red and blue wires have to be installed so that there is an input signal which is then divided into the turn signals. If a diode is installed into either one of these wires, it prevents the input from the running light wire or brake light wire from ever reaching the module......
With that being said...... The placement of the diode is not in question.... the resistor in the system is not in question..... the functioning of the system is PERFRECT.... everything works the way that it should... the ONLY problem that I have is that a regular silicone diode has TOO much forward voltage drop....... I have tried every possible scenario to take the diode out of the brake light wire so that the forward voltage drop is not effecting the brake light.... BUT there is ONLY one way for that diode to be in the system and allow the system to work the way that it should.... and that position is where the diode is at on my wiring diagram.
So... what measurements need to be taken to find out if a 1 amp 20V schottky diode will be fine? I will try to measure the amperage where the current diode is installed.... will this be the only measurement?