* I posted this while you where learning from the TA, hope it helps to reinforce the concept.
If you assume the larger tank has an area of 3000 square inches, and the smaller tank an area of 30 square inches.
Using the pressure = force/area formula the total force the larger tank must withstand in its skin is 150,000 pounds, the smaller tank's skin must withstand 1500 lbs.
The shape of the tank can be a significant factor in designing a pressure vessel.
Lets assume a round tank.
Think of the tank as a series of hoops held together. Each hoop 1 inch wide. for every one inch traveled along the hoop 50 pounds of force is pushing against the skin.
In the small tank lets assume each hoop has a length of 15 inches; each hoop must retain 750 pounds. This force is withstood by the skin and if divided by the area of the cross section of the hoop it is stated as "hoop stress" and expressed in pounds per square inch.
Increasing the volume:
If you keep the diameter of the tank the same and just make it longer the hoop stress in the wall will be virtually the same, so to hold 100 times more air you can just make your tank 100 times longer. It will not fail with the same skin thickness because the 148,500 pounds of additional force will be distributed.
If you make your larger tank the same length a 100 times increase in volume will require it to be 10 times larger in diameter. In this case the skin will need to be thicker because the hoop stress will be much higher. Each one inch wide hoop will be 10 times longer, 150 inches, and subjected to 7500 pounds. The hoop stress will be correspondingly higher.
The numbers I am using for length of hoops is not derived from my stated area changes.
(For you sticklers; I do not want to add confusion so I am omitting the bending induced stress for this explanation.)